X^2-160x+900=0

Solution for X^2-160x+900=0 equation:

X^2-160X+900=0

a = 1; b = -160; c = +900;
Δ = b2-4ac
Δ = -1602-4·1·900
Δ = 22000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{22000}=\sqrt{400*55}=\sqrt{400}*\sqrt{55}=20\sqrt{55}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-160)-20\sqrt{55}}{2*1}=\frac{160-20\sqrt{55}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-160)+20\sqrt{55}}{2*1}=\frac{160+20\sqrt{55}}{2}
$